Auckland Sports College
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"Moving Forward Together"
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This is a calculus course which extends differentiation and calculus concepts to three dimensions. It has both calculus and algebra content
Calculus:
We need the idea of a function of two variables. The volume of a cylinder is πr2h which we write as V(r,h) = πr2h. The radius and the height are independent variables - they can have any value. V(r,h) is a dependent variable as its value depends on the values of 'r' and of 'h''
The graph of a function of two variables is three dimensional : for example z = V(r,h) = πr2h
So, the graph of z = f(x,y) = x2 is a solid parabola which runs along the length of the y-axis. For any value of y, z = x2
A level curve, also called a contour curve of a surface is the set of all values where f(x,y) = c, for some constant term 'c'. An example of contour curves is the 'height above sea level' curves on a topographical map.
A function is a rule that assigns each value in the domain of the function a single value in the range of the function. A vector-valued function (vector function) is a function whose domain is a set of real numbers and whose range is a set of vectors. This course concentrates on functions where x,y,z are functions of t (most commonly t is time).
So, and this is important, r(t) = f(t)i + g(t)j + h(t)j
We write this as r(t) = <f(t), g(t), h(t)> = f(t)i + g(t)j + h(t)jA continuous vector function defines a "space curve" that is the tip of the moving vector. The equations f(t), g(t), and h(t) are parametric equations and 't' is the parameter.
r'(t) = <f'(t), g'(t), h'(t)> = f'(t)i + g'(t)j + h'(t)j
Partial Derivatives The partial derivative of a function of two (or more) variables is the derivative with respect to a single variable. The other variables are treated as constants.
if f(x,y) = x3 + x2y3 - 2y2
then fx(x,y) = 3x2 + 2xy3
and fy(x,y) = 3x2y2 - 4y
The partial derivative is the gradient of the surface in the 'x' or the 'y' direction.
Higher order partial derivatives - fxx means the second partial derivative with respect to 'x'. fxy means the partial derivative with respect to x is calculated first, then the partial derivative with respect to y
If we think of a point, any point, on a 3-dimensional surface (for example part-way up a hill) in which direction is the slope a maximum? In which direction is the slope a minimum?
The first thing we need to do is to calculate the slope in an arbitrary direction 'u' where 'u' is a unit vector and u = ai +bj for some a, b. If 'u' is a unit vector then x = icosθ and y = jsinθ where θ is the positive angle formed by 'u' and the x-axis.
The directional derivative (Du) of a differentiable function f(x,y) in the direction of a unit vector u = < a, b > is
Duf(x,y) = fx(x,y)a + fy(x,y)b
If 'u' makes an angle θ with the positive x-axis then we can write Du as
Duf(x,y) = fx(x,y)cosθ + fy(x,y)sinθ
The vector < fx(x,y), fy(x,y) > is called the gradient of 'f' and is written as ∇f(x,y)
and the formula for the directional derivative can be written as a dot product
Duf(x,y) = ∇f(x,y).u
The maximum value of the directional derivative Du is |∇f(x,y)| and it occurs when the vector u has the same direction as the gradient vector (as the dot product of 2 vectors is |a||b|cosθ and cos is a maximum when &theta = 0.
For a point (x,y), ∇f(x,y) is perpendicular to the level curve through (x,y)
Gradient vectors determine the maximum rate of change. They are a different concept to the maximum and minimum values of a function.
Maximum and Minimum values The point (a,b) is a critical point if fx(a,b) = 0 (or doesn't exist) AND fy(a,b) = 0 (or doesn't exist).
Local maxima and local minima are critical points, but not all critical points are local maxima or local minima. To determine whether a critical point is a local maxima or a local minima we need to use a second derivative test.
If (a,b) is a critical point of 'f', define
D = D(a,b) = fxx(a,b)fyy(a,b) - (fxy(a,b))2
if D > 0 and fxx(a,b) > 0, then (a,b) is a local minimum
if D > 0 and fxx(a,b) < 0, then (a,b) is a local maximum
if D < 0 then (a,b) is a saddle point
To find the global maximum and the global minimum (the extreme values) all the critical points must be evaluated as well as any boundary points.